Let: A + B = C And: 2A - A = A 2B - B = B 2C - C = C Now sub the three equations into the first. (2A-A) + (2B-B) = (2C-C) Move all twos on one side and all singles on the other. 2A + 2B - 2C = A + B - C Factor. 2(A + B - C) = 1(A + B - C) Cancel out like terms: 2 = 1 Math-a-magic
And for my next trick.... Think of a number, any number... now mutiply it by two... Add six to it... Divide it by two... Subtract you origional number... Your final number is... 3